2n^2+3n-7=2

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Solution for 2n^2+3n-7=2 equation:


Simplifying
2n2 + 3n + -7 = 2

Reorder the terms:
-7 + 3n + 2n2 = 2

Solving
-7 + 3n + 2n2 = 2

Solving for variable 'n'.

Reorder the terms:
-7 + -2 + 3n + 2n2 = 2 + -2

Combine like terms: -7 + -2 = -9
-9 + 3n + 2n2 = 2 + -2

Combine like terms: 2 + -2 = 0
-9 + 3n + 2n2 = 0

Factor a trinomial.
(-3 + -1n)(3 + -2n) = 0

Subproblem 1

Set the factor '(-3 + -1n)' equal to zero and attempt to solve: Simplifying -3 + -1n = 0 Solving -3 + -1n = 0 Move all terms containing n to the left, all other terms to the right. Add '3' to each side of the equation. -3 + 3 + -1n = 0 + 3 Combine like terms: -3 + 3 = 0 0 + -1n = 0 + 3 -1n = 0 + 3 Combine like terms: 0 + 3 = 3 -1n = 3 Divide each side by '-1'. n = -3 Simplifying n = -3

Subproblem 2

Set the factor '(3 + -2n)' equal to zero and attempt to solve: Simplifying 3 + -2n = 0 Solving 3 + -2n = 0 Move all terms containing n to the left, all other terms to the right. Add '-3' to each side of the equation. 3 + -3 + -2n = 0 + -3 Combine like terms: 3 + -3 = 0 0 + -2n = 0 + -3 -2n = 0 + -3 Combine like terms: 0 + -3 = -3 -2n = -3 Divide each side by '-2'. n = 1.5 Simplifying n = 1.5

Solution

n = {-3, 1.5}

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